Evaluate sum of cotangent and tangent

Given $\text{cosec}\, \theta = \frac{13}{12} \implies \sin \theta = \frac{12}{13}$. Then $\cos \theta = \sqrt{1 - (12/13)^2} = \frac{5}{13}$. $\cot \theta + \tan \theta = \frac{\cos \theta}{\sin \theta} + \frac{\sin \theta}{\cos \theta} = \frac{\cos^2 \theta + \sin^2 \theta}{\sin \theta \cos \theta} = \frac{1}{\sin \theta \cos \theta}$ $\cot \theta + \tan \theta = \frac{1}{(12/13)(5/13)} = \frac{169}{60}$