Sum of squares of natural numbers word problem

Let the first natural number be $x$. The second number is $y = 2x + 1$. Given $x^2 + y^2 = 29$: $x^2 + (2x + 1)^2 = 29$ $x^2 + 4x^2 + 4x + 1 = 29$ $5x^2 + 4x - 28 = 0$ $5x^2 + 14x - 10x - 28 = 0$ $x(5x + 14) - 2(5x + 14) = 0$ $(x - 2)(5x + 14) = 0$ Since $x$ is a natural number, $x = 2$. Second number $= 2(2) + 1 = 5$. The numbers are 2 and 5.