Question

For the given data: | Class-Interval | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 | |---|---|---|---|---|---| | Frequency | 2 | 10 | 4 | 8 | 6 | Sum of upper limits of median class and modal class of above data is

Accepted Answer

C. Cumulative frequencies are $2, 12, 16, 24, 30$. $N = 30 \implies \frac{N}{2} = 15$. The cumulative frequency just greater than 15 is 16, which corresponds to class interval $10 - 15$. So upper limit of median class $= 15$. Maximum frequency is 10, corresponding to class interval $5 - 10$. So upper limit of modal class $= 10$. Sum $= 15 + 10 = 25$.

Sum of upper limits of median and modal class

Explanation

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