Question

**Assertion (A):** The number $12^n$ ends with digit 0 where '$n$' is a natural number. **Reason (R):** Any number ends with digit 0 if its prime factor is of the form $2^m 	imes 5^n$, where '$m$' and '$n$' are natural numbers.

Accepted Answer

D. $12^n = (2^2 	imes 3)^n = 2^{2n} 	imes 3^n$. Prime factorisation of 12 does not contain 5, so $12^n$ can never end with 0. Thus Assertion (A) is false, and Reason (R) is true.

Ending digit of 12^n

Explanation

Practise this under board exam conditions