Question

Find the co-ordinates of point A, where AB is diameter of the circle whose centre is $(2, -3)$ and B is $(1, 4)$.

Accepted Answer

Let $A(x, y)$. Centre $(2, -3)$ is the midpoint of diameter AB. $\frac{x + 1}{2} = 2 \implies x = 3$. $\frac{y + 4}{2} = -3 \implies y = -10$. Therefore, coordinates of A are $(3, -10)$.

Coordinates of endpoint of diameter

Explanation

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