Question

In the given figure, there is a circle with centre 'O' having three tangents at points P, T and S. If $QR = 12	ext{ cm}$ and radius of a circle is $7	ext{ cm}$, then perimeter of polygon PQRSO is :

Accepted Answer

C. Tangents from Q give $QP = QT$ and tangents from R give $RS = RT$. Thus, $QP + RS = QT + RT = QR = 12	ext{ cm}$. Perimeter of polygon PQRSO $= PQ + QR + RS + SO + OP = (PQ + RS) + QR + SO + OP = 12 + 12 + 7 + 7 = 38	ext{ cm}$.

Perimeter of polygon around circle

Explanation

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