Zeroes of a quadratic polynomial

To find the zeroes of the polynomial $p(x) = x^2 - x - 6$, we set $p(x) = 0$: $x^2 - x - 6 = 0$ We can factorize the quadratic equation: $x^2 - 3x + 2x - 6 = 0$ $x(x - 3) + 2(x - 3) = 0$ $(x + 2)(x - 3) = 0$ This gives two possible values for $x$: $x + 2 = 0 \implies x = -2$ $x - 3 = 0 \implies x = 3$ So, the zeroes of the polynomial are $3$ and $-2$.