Value of p for polynomial zeroes

Given the polynomial $f(x) = px^2 - 2x + 3p$. The general form of a quadratic polynomial is $ax^2 + bx + c$. Here, $a = p$, $b = -2$, $c = 3p$. For a quadratic polynomial, the sum of the zeroes ($\alpha + \beta$) is given by $-\frac{b}{a}$, and the product of the zeroes ($\alpha\beta$) is given by $\frac{c}{a}$. So, $\alpha + \beta = -\frac{-2}{p} = \frac{2}{p}$ And $\alpha\beta = \frac{3p}{p} = 3$ We are given the condition $\alpha + \beta - \alpha\beta = 0$. Substitute the expressions for $\alpha + \beta$ and $\alpha\beta$: $\frac{2}{p} - 3 = 0$ $\frac{2}{p} = 3$ $2 = 3p$ $p = \frac{2}{3}$ Thus, the value of $p$ is $\frac{2}{3}$.